Objective
if and else are two of the most frequently used conditionals in C/C++, and they enable you to execute zero or one conditional statement among many such dependent conditional statements. We use them in the following ways:
if
: This executes the body of bracketed code starting with if evaluates to true.if (condition) { statement1; ... }
if - else
: This executes the body of bracketed code starting with if evaluates to true, or it executes the body of code starting with if evaluates to false. Note that only one of the bracketed code sections will ever be executed.if (condition) { statement1; ... } else { statement2; ... }
if - else if - else
: In this structure, dependent statements are chained together and the for each statement is only checked if all prior conditions in the chain are evaluated to false. Once a evaluates to true, the bracketed code associated with that statement is executed and the program then skips to the end of the chain of statements and continues executing. If each in the chain evaluates to false, then the body of bracketed code in the else block at the end is executed.if(first condition) { ... } else if(second condition) { ... } . . . else if((n-1)'th condition) { .... } else { ... }
Task
Given a positive integer denoting , do the following:
- If , then print the lowercase English word corresponding to the number (e.g.,
one
for ,two
for , etc.). - If , print
Greater than 9
.
Input Format
The first line contains a single integer denoting .
Constraints
Output Format
If , then print the lowercase English word corresponding to the number (e.g., one
for , two
for , etc.); otherwise, print Greater than 9
instead.
Sample Input
5
Sample Output
five
Sample Input #01
8
Sample Output #01
eight
Sample Input #02
44
Sample Output #02
Greater than 9
Now here's the solution in C:-
code snippet:#include<stdio.h>
int main()
{
int n;
scanf("%d\n",&n);
if(1<=n && n<=9)
{
if(n==1)
{
printf("one\n");
}
else if(n==2)
{
printf("two\n");
}
else if(n==3)
{
printf("three\n");
}
else if(n==4)
{
printf("four\n");
}
else if(n==5)
{
printf("five\n");
}
else if(n==6)
{
printf("six\n");
}
else if(n==7)
{
printf("seven\n");
}
else if(n==8)
{
printf("eight\n");
}
else
{
printf("nine\n");
}
}
else if(n>9)
{
printf("Greater than 9\n");
}
// Write Your Code Here
return 0;
}
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ReplyDeletethank you for this solution my was small mistake but understood by seeing your program
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