Objective
The fundamental data types in c are int, float and char. Today, we're discussing int and float data types.
The printf()
function prints the given statement to the console. The syntax is printf("format string",argument_list);
. In the function, if we are using an integer, character, string or float as argument, then in the format string we have to write %d
(integer), %c
(character), %s
(string), %f
(float) respectively.
The scanf()
function reads the input data from the console. The syntax is scanf("format string",argument_list);
. For ex: The scanf("%d",&number)
statement reads integer number from the console and stores the given value in variable .
To input two integers separated by a space on a single line, the command is scanf("%d %d", &n, &m)
, where and are the two integers.
Task
Your task is to take two numbers of int data type, two numbers of float data type as input and output their sum:
- Declare variables: two of type int and two of type float.
- Read lines of input from stdin (according to the sequence given in the 'Input Format' section below) and initialize your variables.
- Use the and operator to perform the following operations:
- Print the sum and difference of two int variable on a new line.
- Print the sum and difference of two float variable rounded to one decimal place on a new line.
Input Format
The first line contains two integers.
The second line contains two floating point numbers.
Constraints
- integer variables
- float variables
Output Format
Print the sum and difference of both integers separated by a space on the first line, and the sum and difference of both float (scaled to decimal place) separated by a space on the second line.
Sample Input
10 4
4.0 2.0
Sample Output
14 6
6.0 2.0
Explanation
When we sum the integers and , we get the integer . When we subtract the second number from the first number , we get as their difference.
When we sum the floating-point numbers and , we get . When we subtract the second number from the first number , we get as their difference.
Now here's the solution in C:-
code snippet:#include <stdio.h>#include <math.h>int main(){ int a,b; float c,d; scanf("%d %d\n%f %f",&a,&b,&c,&d); printf("%d %d\n",a+b,a-b); printf("%0.1f %0.1f\n",c+d,c-d); return 0;}
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