Sum of Series||C language||programming_info ||Series problem 3

To find out the sum of series 1^2 + 2^2 + …. + n^2

Solution using c language:

1. #include<stdio.h>
2. int main() {
3. int n,i;
4. int sum=0;
5. printf("Enter the n i.e. max values of series: ");
6. scanf("%d",&n);
7. sum = (n * (n + 1) * (2 * n + 1 )) / 6;
8. printf("Sum of the series : ");
9. for (i =1;i<=n;i++) {
10. if (i != n)
11. printf("%d^2 + ",i); else
12. printf("%d^2 = %d ",i,sum);
13. }
14. return 0;
15. }

Output:

Enter the n i.e. max values of series: 5
Sum of the series: 1^2 + 2^2 + 3^2 + 4^2 + 5^2 = 55

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