Fibonacci Series||C language||programming_info ||Series problem 1

Fibonacci Series

 Solution using C language:

#include<stdio.h>
int main(){
int i,range;
 long int arr[40];
 
printf("Enter the number range: ");
 scanf("%d",&range);
 
arr[0]=0;
arr[1]=1;
 
for(i=2;i<range;i++){
arr[i] = arr[i-1] + arr[i-2];
}
 
printf("Fibonacci series is: ");
for(i=0;i<range;i++)
 printf("%ld ",arr[i]);
   return 0;
}
Output:
Enter the number range: 20
Fibonacci series is: 0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181
Alternate Solution using While loop in c:


#include<stdio.h>
int main(){
int k=2,r;
long int i=0l,j=1,f;
printf("Enter the number range:");
 scanf("%d",&r);
 printf("Fibonacci series is: %ld %ld",i,j);
 
 while(k<r){
 f=i+j;
 i=j;
 j=f;
 printf(" %ld",j);
 k++;
 }
 return 0;
}



Output:
Enter the number range: 10
Fibonacci series is: 0 1 1 2 3 5 8 13 21 34




Alternate Solution using recursion in c:


#include <stdio.h>
#include <conio.h>
unsigned long fib(int);
void main()
{
int n,i;
unsigned long f;
clrscr();
printf("\nENTER A NUMBER: ");
scanf("%d",&n);
printf("\nTHE FIBONNACI SERIES UPTO %d NUMBERS IS:\n",n);
for(i=0;i<n;i++)
{
f=fib(i);
printf("%lu ",f);
}
getch();
}
unsigned long fib(int x)
{
unsigned long res;
if(x==0)
return(0);
else
if(x==1)
return(1);
else
{
res=fib(x-1)+fib(x-2);
return(res);
}
}
Output:
ENTER A NUMBER: 10
THE FIBONNACI SERIES UPTO 10 NUMBERS IS
0 1 1 2 3 5 8 13 21 34

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