Neon Number solution using c language--programming_info problem 22

Neon Number:

#include <stdio.h>

#include <stdlib.h>

 

int main()

{

    int n, digit, sum =0;

 

    printf("Enter a number to check for neon Number \n");

 

    scanf("%d",&n);

    int sq = n*n;

 

    while(sq!=0){

        digit = sq % 10;

        sum += digit;

        sq = sq/10;

    }

 

    if(sum == n)

        printf("Neon Number \n");

    else

        printf("Not a Neon Number \n");

 

    return 0;

}

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