Objective
In this challenge, we're getting started with conditional statements. Check out the Tutorial tab for learning materials and an instructional video!
Task
Given an integer, , perform the following conditional actions:
- If is odd, print
Weird - If is even and in the inclusive range of to , print
Not Weird - If is even and in the inclusive range of to , print
Weird - If is even and greater than , print
Not Weird
Complete the stub code provided in your editor to print whether or not is weird.
Input Format
A single line containing a positive integer, .
Constraints
Output Format
Print Weird if the number is weird; otherwise, print Not Weird.
Sample Input 0
3
Sample Output 0
Weird
Sample Input 1
24
Sample Output 1
Not Weird
Explanation
Sample Case 0:
is odd and odd numbers are weird, so we print Weird.
Sample Case 1:
and is even, so it isn't weird. Thus, we print Not Weird.
Now here's the solution in C/C++/JAVA:-
code snippet:
1.using c++ language:
int main(){
int n;
cin >> n;
if ((n & 1) || (6 <= n && n <= 20))
cout << "Weird" << endl;
else
cout << "Not Weird" << endl;
return 0
alternate solution:-
#include <bits/stdc++.h>
using namespace std;
int main()
{
int N;
cin >> N;
cin.ignore(numeric_limits<streamsize>::max(), '\n');
if(N%2==0)
{
if(2<=N && N<5)
{
cout<<"Not Weird"<<endl;
}
else if(6<=N && N<=20)
{
cout<<"Weird"<<endl;
}
else if(N>20)
cout<<"Not Weird"<<endl;
}
else
cout<<"Weird"<<endl;
return 0;
}
2.using java language:
import java.util.*;
public class Solution {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
scan.close();
System.out.println( ((n & 1) == 1 || (6 <= n && n <= 20)) ? "Weird" : "Not Weird");
}
}
alternate solution:-
import java.util.*;
public class Solution {
private static String weird = "Weird";
private static String notWeird = "Not Weird";
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
scan.close();
String ans="";
// if 'n' is NOT evenly divisible by 2 (i.e.: n is odd)
if(n%2==1){
ans = weird;
}
// 'n' must be even; proceed if 'n' >= 2
else if(n >= 2){
if(n > 20){
ans = notWeird;
}
else if(n >= 6){
ans = weird;
}
else if(n >= 2){
ans = notWeird;
}
}
System.out.println(ans);
}
}
3.using c language:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
int N;
scanf("%d",&N);
if(N%2==0)
{
if(2<=N && N<5)
{
printf("Not Weird");
}
else if(6<=N && N<=20)
{
printf("Weird");
}
else if(N>20)
printf("Not Weird");
}
else
printf("Weird");
return 0;
}
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