1+1/2+1/3+1/4+.....N
Solution using C language:
#include<stdio.h>
int main()
{
int i, N;
float sum=0;
printf("Enter N:");
scanf("%d", &N);
if(N<1){
printf("Enter value of N > 0.");
exit(1);
}
for(i=1; i<=N; i++)
{
if(i==1)
{
sum=1;
printf("Series = 1");
}
else
{
sum = sum + (float)1/i;
printf(" + 1/%d", i);
}
}
printf("\nSum of the series = %0.2f", sum);
return 0;
}
Output:
Enter N:5
Series = 1 + 1/2 + 1/3 + 1/4 + 1/5
Sum of the series = 2.28
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