Lucky Four ||codechef||beginner solution ||programming info

Lucky Four

Kostya likes the number 4 much. Of course! This number has such a lot of properties, like:

• Four is the smallest composite number;
• It is also the smallest Smith number;
• The smallest non-cyclic group has four elements;
• Four is the maximal degree of the equation that can be solved in radicals;
• There is four-color theorem that states that any map can be colored in no more than four colors in such a way that no two adjacent regions are colored in the same color;
• Lagrange's four-square theorem states that every positive integer can be written as the sum of at most four square numbers;
• Four is the maximum number of dimensions of a real division algebra;
• In bases 6 and 12, 4 is a 1-automorphic number;
• And there are a lot more cool stuff about this number!

Impressed by the power of this number, Kostya has begun to look for occurrences of four anywhere. He has a list of T integers, for each of them he wants to calculate the number of occurrences of the digit 4 in the decimal representation. He is too busy now, so please help him.

Input

The first line of input consists of a single integer T, denoting the number of integers in Kostya's list.

Then, there are T lines, each of them contain a single integer from the list.

Output

Output T lines. Each of these lines should contain the number of occurences of the digit 4 in the respective integer from Kostya's list.

Constraints

• 1 ≤ T ≤ 10⁵
• (Subtask 1): 0 ≤ Numbers from the list ≤ 9 - 33 points.
• (Subtask 2): 0 ≤ Numbers from the list ≤ 10⁹ - 67 points.

Example

Input:
5
447474
228
6664
40
81

Output:
4
0
1
1
0

SOLUTION USING C LANGUAGE:-
#include <stdio.h>
#include<string.h>
int main(void)
    {
        int T,i,N,s,r;
        scanf("%d",&T);
        for(i=0;i<T;i++)
            {
                scanf("%d\n",&N);
                s=0;
                while(N!=0)
                    {
                        r=N%10;
                        if(r==4)
                            {
                                s=s+1;
                            }
                        N=N/10;
                    }
                printf("%d\n",s);
            }
    	// your code goes here
    	return 0;
    }

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